Difference between revisions of "2012 AMC 12B Problems/Problem 1"

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                  == Problem ==
+
== Problem ==
 
   
 
   
 
Each third-grade classroom at Pearl Creek Elementary has 18 students and 2 pet rabbits. How many more students than rabbits are there in all 4 of the third-grade classrooms?
 
Each third-grade classroom at Pearl Creek Elementary has 18 students and 2 pet rabbits. How many more students than rabbits are there in all 4 of the third-grade classrooms?
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  <math> \textbf{(A)}\ 48\qquad\textbf{(B)}\ 56\qquad\textbf{(C)}\ 64\qquad\textbf{(D)}\ 72\qquad\textbf{(E)}\ 80 </math>
 
  <math> \textbf{(A)}\ 48\qquad\textbf{(B)}\ 56\qquad\textbf{(C)}\ 64\qquad\textbf{(D)}\ 72\qquad\textbf{(E)}\ 80 </math>
  
                == Solution ==
+
== Solution ==
 
Multiplying 18 and 2 by 4 we get 72 and 8 students and rabbits respectively. Subtracting 72 from 8 we get  
 
Multiplying 18 and 2 by 4 we get 72 and 8 students and rabbits respectively. Subtracting 72 from 8 we get  
 
       64 which is choice '''C'''
 
       64 which is choice '''C'''

Revision as of 19:46, 23 February 2012

Problem

Each third-grade classroom at Pearl Creek Elementary has 18 students and 2 pet rabbits. How many more students than rabbits are there in all 4 of the third-grade classrooms?

$\textbf{(A)}\ 48\qquad\textbf{(B)}\ 56\qquad\textbf{(C)}\ 64\qquad\textbf{(D)}\ 72\qquad\textbf{(E)}\ 80$

Solution

Multiplying 18 and 2 by 4 we get 72 and 8 students and rabbits respectively. Subtracting 72 from 8 we get

      64 which is choice C