Difference between revisions of "2012 AMC 8 Problems/Problem 21"

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==Solution==
 
==Solution==
If Marla evenly distributes her <math>300</math> square feet of paint between the 6 faces, each face will get <math>300\div6 = 50</math> square feet of paint. The surface area of one of the faces of the cube is <math>10^2 = 100 </math> square feet. Therefore, there will be <math>100-50 = \boxed{\textbf{(D)}\ 50} </math> square feet of white on each side.
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If Jenica evenly distributes her <math>300</math> square feet of paint between the 6 faces, each face will get <math>300\div6 = 50</math> square feet of paint. The surface area of one of the faces of the cube is <math>10^2 = 100 </math> square feet. Therefore, there will be <math>100-50 = \boxed{\textbf{(D)}\ 50} </math> square feet of white on each side.
  
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2012|num-b=20|num-a=22}}
 
{{AMC8 box|year=2012|num-b=20|num-a=22}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 01:06, 27 December 2021

Problem

Jenica has a large white cube that has an edge of 10 feet. She also has enough green paint to cover 300 square feet. Marla uses all the paint to create a white square centered on each face, surrounded by a green border. What is the area of one of the white squares, in square feet? $\textbf{(A)}\hspace{.05in}5\sqrt2\qquad\textbf{(B)}\hspace{.05in}10\qquad\textbf{(C)}\hspace{.05in}10\sqrt2\qquad\textbf{(D)}\hspace{.05in}50\qquad\textbf{(E)}\hspace{.05in}50\sqrt2$

Solution

If Jenica evenly distributes her $300$ square feet of paint between the 6 faces, each face will get $300\div6 = 50$ square feet of paint. The surface area of one of the faces of the cube is $10^2 = 100$ square feet. Therefore, there will be $100-50 = \boxed{\textbf{(D)}\ 50}$ square feet of white on each side.

See Also

2012 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 20
Followed by
Problem 22
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All AJHSME/AMC 8 Problems and Solutions

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