Difference between revisions of "2012 AMC 8 Problems/Problem 23"
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Revision as of 16:39, 3 July 2013
Problem
An equilateral triangle and a regular hexagon have equal perimeters. If the area of the triangle is 4, what is the area of the hexagon?
Solution
Let the perimeter of the equilateral triangle be 
. The side length of the equilateral triangle would then be 
and the sidelength of the hexagon would be 
.
A hexagon contains six equilateral triangles. One of these triangles would be similar to the large equilateral triangle in the ratio 
, since the sidelength of the small equilateral triangle is half the sidelength of the large one. Thus, the area of one of the small equilateral triangles is 
. The area of the hexagon is then 
.
See Also
| 2012 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 22 |
Followed by Problem 24 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
