Difference between revisions of "2013 AMC 10B Problems/Problem 4"

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==Problem==
 
==Problem==
When counting from <math>3</math> to <math>201</math>, <math>53</math> is the <math>51st</math> number counted. When counting backwards from <math>201</math> to <math>3</math>, <math>53</math> is the <math>nth</math> number counted. What is <math>n</math>?
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When counting from <math>3</math> to <math>201</math>, <math>53</math> is the <math>51^\mathrm{st}</math> number counted. When counting backwards from <math>201</math> to <math>3</math>, <math>53</math> is the <math>n^\mathrm{th}</math> number counted. What is <math>n</math>?
  
<math>\textbf{(A) } 146</math>
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<math>\textbf{(A)}\ 146\qquad\textbf{(B)}\ 147\qquad\textbf{(C)}\ 148\qquad\textbf{(D)}\ 149\qquad\textbf{(E)}\ 150</math>
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==Solution==

Revision as of 17:11, 21 February 2013

Problem

When counting from $3$ to $201$, $53$ is the $51^\mathrm{st}$ number counted. When counting backwards from $201$ to $3$, $53$ is the $n^\mathrm{th}$ number counted. What is $n$?

$\textbf{(A)}\ 146\qquad\textbf{(B)}\ 147\qquad\textbf{(C)}\ 148\qquad\textbf{(D)}\ 149\qquad\textbf{(E)}\ 150$

Solution