Difference between revisions of "2013 AMC 12A Problems/Problem 1"

Revision as of 00:51, 8 February 2013

We are given that the area of $\triangle ABE$ is $40$ , and that $AB = 10$ .

The area of a triangle:

$A = \frac{bh}{2}$

Using $AB$ as the height of $\triangle ABE$ ,

$40 = \frac{10b}{2}$

and solving for b,

$b = 8$ , which is $E$

Revision as of 04:15, 7 February 2013 (view source) Epicwisdom (talk \| contribs) (LaTeX formatting) ← Older edit		Revision as of 00:51, 8 February 2013 (view source) Indianninja707 (talk \| contribs) Newer edit →
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	and solving for b,		and solving for b,

−	<math>b = 8</math>	+	<math>b = 8</math>, which is <math>E</math>