# Difference between revisions of "2013 AMC 12A Problems/Problem 1"

(Created page with "We know that the Area of a triangle is (bh)/2, so we can figure out that b=2A/h A=40 h=10 Therefore, b=80/10, which is 8, or E") |
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− | We | + | We are given that the area of ∆ABE is 40, and that side AB is of length 10. |

− | + | Side AB can be used as the height of ∆ABE. | |

− | A= | + | Since A= (bh)/2, |

− | |||

− | + | 40=(10h)/2 | |

− | + | ||

+ | and solving for h will give us 8, or E. |

## Revision as of 21:37, 6 February 2013

We are given that the area of ∆ABE is 40, and that side AB is of length 10.

Side AB can be used as the height of ∆ABE.

Since A= (bh)/2,

40=(10h)/2

and solving for h will give us 8, or E.