Difference between revisions of "2013 AMC 12A Problems/Problem 1"

(Created page with "We know that the Area of a triangle is (bh)/2, so we can figure out that b=2A/h A=40 h=10 Therefore, b=80/10, which is 8, or E")
 
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We know that the Area of a triangle is (bh)/2, so we can figure out that  
+
We are given that the area of ∆ABE is 40, and that side AB is of length 10.
  
b=2A/h
+
Side AB can be used as the height of ∆ABE.
  
A=40
+
Since A= (bh)/2,
h=10
 
  
Therefore, b=80/10,
+
40=(10h)/2
which is 8, or E
+
 
 +
and solving for h will give us 8, or E.

Revision as of 21:37, 6 February 2013

We are given that the area of ∆ABE is 40, and that side AB is of length 10.

Side AB can be used as the height of ∆ABE.

Since A= (bh)/2,

40=(10h)/2

and solving for h will give us 8, or E.

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