Difference between revisions of "2013 AMC 12A Problems/Problem 1"

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and solving for b,
and solving for b,
<math>b = 8</math>
<math>b = 8</math>, which is <math>E</math>

Revision as of 00:51, 8 February 2013

We are given that the area of $\triangle ABE$ is $40$, and that $AB = 10$.

The area of a triangle:

$A = \frac{bh}{2}$

Using $AB$ as the height of $\triangle ABE$,

$40 = \frac{10b}{2}$

and solving for b,

$b = 8$, which is $E$

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