2013 AMC 12A Problems/Problem 10
Revision as of 23:05, 6 February 2013 by Epicwisdom (talk | contribs) (Created page with "Note that <math>\frac{1}{11} = 0.\overline{09}</math>. Dividing by 3 gives <math>\frac{1}{33} = 0.\overline{03}</math>, and dividing by 9 gives <math>\frac{1}{99} = 0.\overline{...")
Note that 
.
Dividing by 3 gives 
, and dividing by 9 gives 
.
The answer must be at least 
, but cannot be 
since no 
other than 
satisfies the conditions, so the answer is .
