Difference between revisions of "2013 AMC 12A Problems/Problem 9"
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Since opposite sides of parallelograms are equal, the perimeter is <math>2 * (AD + DE) = | Since opposite sides of parallelograms are equal, the perimeter is <math>2 * (AD + DE) = | ||
\boxed{\textbf{(C) }{56}}</math>. | \boxed{\textbf{(C) }{56}}</math>. | ||
+ | |||
+ | ==Video Solution== | ||
+ | https://youtu.be/CCjcMVtkVaQ | ||
+ | |||
+ | ~sugar_rush | ||
== See also == | == See also == |
Latest revision as of 17:02, 24 November 2020
Contents
Problem
In , and . Points and are on sides , , and , respectively, such that and are parallel to and , respectively. What is the perimeter of parallelogram ?
Solution
Note that because and are parallel to the sides of , the internal triangles and are similar to , and are therefore also isosceles triangles.
It follows that . Thus, .
Since opposite sides of parallelograms are equal, the perimeter is .
Video Solution
~sugar_rush
See also
2013 AMC 12A (Problems • Answer Key • Resources) | |
Preceded by Problem 8 |
Followed by Problem 10 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
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