Difference between revisions of "2013 AMC 12B Problems/Problem 2"

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{{duplicate|[[2013 AMC 12B Problems|2013 AMC 12B #2]] and [[2013 AMC 10B Problems|2013 AMC 10B #2]]}}
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==Problem==
 
==Problem==
 
Mr. Green measures his rectangular garden by walking two of the sides and finds that it is <math>15</math> steps by <math>20</math> steps. Each of Mr. Green's steps is <math>2</math> feet long. Mr. Green expects a half a pound of potatoes per square foot from his garden. How many pounds of potatoes does Mr. Green expect from his garden?
 
Mr. Green measures his rectangular garden by walking two of the sides and finds that it is <math>15</math> steps by <math>20</math> steps. Each of Mr. Green's steps is <math>2</math> feet long. Mr. Green expects a half a pound of potatoes per square foot from his garden. How many pounds of potatoes does Mr. Green expect from his garden?

Revision as of 10:28, 7 April 2013

The following problem is from both the 2013 AMC 12B #2 and 2013 AMC 10B #2, so both problems redirect to this page.

Problem

Mr. Green measures his rectangular garden by walking two of the sides and finds that it is $15$ steps by $20$ steps. Each of Mr. Green's steps is $2$ feet long. Mr. Green expects a half a pound of potatoes per square foot from his garden. How many pounds of potatoes does Mr. Green expect from his garden?

$\textbf{(A)}\ 600 \qquad \textbf{(B)}\ 800 \qquad \textbf{(C)}\ 1000 \qquad \textbf{(D)}\ 1200 \qquad \textbf{(E)}\ 1400$

Solution

Since each step is $2$ feet, his garden is $30$ by $40$ feet. Thus, the area of $30(40) = 1200$ square feet. Since he is expecting $\frac{1}{2}$ of a pound per square foot, the total amount of potatoes expected is $1200 \times \frac{1}{2} =  \boxed{\textbf{(A) }600}$

See also

2013 AMC 12B (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
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All AMC 12 Problems and Solutions
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