Difference between revisions of "2013 UNCO Math Contest II Problems/Problem 5"

m
(Solution)
(One intermediate revision by one other user not shown)
Line 5: Line 5:
 
<math>2+3+4+4+4</math>, etc., which have repeated terms. You need not justify your answer on this question.
 
<math>2+3+4+4+4</math>, etc., which have repeated terms. You need not justify your answer on this question.
  
<math>\begin{tabular}{|c|c|c|c|}
+
<math>\begin{array}{|c|c|c|c|}
 
\hline
 
\hline
EXAMPLE: & Distinct Integers: {2, 3, 4, 8} & Their Sum: 2+3+4+8=17 & Their Product: 2 \times 3\times 4\times 8=192 \\
+
\text{EXAMPLE: }& \text{Distinct Integers: }{2, 3, 4, 8} & \text{Their Sum: }2+3+4+8=17 & \text{Their Product: }2 \times 3\times 4\times 8=192 \\
 
\hline
 
\hline
\end{tabular}</math>
+
\end{array}</math>
 
 
 
 
  
 
== Solution ==
 
== Solution ==
 
+
<math>\{2, 4, 5, 6\}.</math> The product is <math>240</math>
  
 
== See Also ==
 
== See Also ==

Revision as of 03:28, 13 January 2019

Problem

If the sum of distinct positive integers is $17$, find the largest possible value of their product. Give both a set of positive integers and their product. Remember to consider only sums of distinct numbers, and not $3+7+7$ or $2+3+4+4+4$, etc., which have repeated terms. You need not justify your answer on this question.

$\begin{array}{|c|c|c|c|} \hline \text{EXAMPLE: }& \text{Distinct Integers: }{2, 3, 4, 8} & \text{Their Sum: }2+3+4+8=17 & \text{Their Product: }2 \times 3\times 4\times 8=192 \\ \hline \end{array}$

Solution

$\{2, 4, 5, 6\}.$ The product is $240$

See Also

2013 UNCO Math Contest II (ProblemsAnswer KeyResources)
Preceded by
Problem 4
Followed by
Problem 6
1 2 3 4 5 6 7 8 9 10
All UNCO Math Contest Problems and Solutions