2013 USAJMO Problems/Problem 6

Revision as of 10:55, 14 April 2014 by Suli (talk | contribs) (Solution)

Solution

Without loss of generality, let $x \ge y \ge z$. Then $\sqrt{x + xyz} = \sqrt{x - 1} + \sqrt{y - 1} + \sqrt{z - 1}$.