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2013 USAJMO Problems/Problem 6

Revision as of 10:56, 14 April 2014 by Suli (talk | contribs) (→‎Solution)

Solution

Without loss of generality, let $x \le y \le z$. Then $\sqrt{x + xyz} = \sqrt{x - 1} + \sqrt{y - 1} + \sqrt{z - 1}$.

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