Difference between revisions of "2014 AIME II Problems/Problem 15"
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| − | + | ==Solution== | |
| + | Note that in base 2 <math>a_1</math> = 2, <math>a_10</math> = 3, <math>a_11</math> = 2 * 3 = 6, ..., <math>a_10010101</math> = 2 * 5 * 11 * 19 = 2090. Thus, t = 10010101 (base 2) = <math>\boxed{149}</math>. | ||
Revision as of 10:52, 28 March 2014
Solution
Note that in base 2 
= 2, 
= 3, 
= 2 * 3 = 6, ..., 
= 2 * 5 * 11 * 19 = 2090. Thus, t = 10010101 (base 2) = 
.
