2014 AIME I Problems/Problem 2

Revision as of 09:05, 14 March 2014 by Test48 (talk | contribs) (Undo revision 60870 by Agrgordon (talk))


Solution 1:The probability of drawing balls of the same color is the sum of the probabilities of drawing two green balls and of drawing two blue balls. This give us $\frac{29}{50} = \frac{2}{5} \cdot \frac{16}{16+N} + \frac{3}{5} \cdot \frac{N}{16 + N}$

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