2014 AMC 10A Problems/Problem 4

Revision as of 23:54, 6 February 2014 by Joshualee2000 (talk | contribs) (Solution)

Problem

Walking down Jane Street, Ralph passed four houses in a row, each painted a different color. He passed the orange house before the red house, and he passed the blue house before the yellow house. The blue house was not next to the yellow house. How many orderings of the colored houses are possible?

$\textbf{(A)}\ 2\qquad\textbf{(B)}\ 3\qquad\textbf{(C)}\ 4\qquad\textbf{(D)}}\ 5\qquad\textbf{(E)}\ 6$ (Error compiling LaTeX. Unknown error_msg)


Solution

Attack this problem with very simple casework. The only possible locations for the yellow house $(Y)$ is the $3$rd house and the last house.

Case 1: $Y$ is the $3$rd house.

The only possible arrangement is $B-O-Y-R$

Case 2: $Y$ is the last house.

There are two possible ways:

$B-O-R-Y$ and

$O-B-R-Y$ so our answer is $\boxed{\textbf{(B)} 3}$

See Also

2014 AMC 10A (ProblemsAnswer KeyResources)
Preceded by
Problem 3
Followed by
Problem 5
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

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