# 2014 AMC 10A Problems/Problem 5

The following problem is from both the 2014 AMC 12A #5 and 2014 AMC 10A #5, so both problems redirect to this page.

## Problem

On an algebra quiz, $10\%$ of the students scored $70$ points, $35\%$ scored $80$ points, $30\%$ scored $90$ points, and the rest scored $100$ points. What is the difference between the mean and median score of the students' scores on this quiz?

$\textbf{(A)}\ 1\qquad\textbf{(B)}\ 2\qquad\textbf{(C)}\ 3\qquad\textbf{(D)}}\ 4\qquad\textbf{(E)}\ 5$ (Error compiling LaTeX. ! Extra }, or forgotten \$.)

## Solution

Without loss of generality, let there be $20$ students(the least whole number possible) who took the test. We have $2$ students score $70$ points, $7$ students score $80$ points, $6$ students score $90$ points and $5$ students score $100$ points.

The median can be obtained by eliminating members from each group. The median is $90$ points.

The mean is equal to the total number of points divided by the number of people, which gives $87$

Thus, the difference between the median and the mean is equal to $90-87=\boxed{\textbf{(C)}\ 3}$