Difference between revisions of "2014 AMC 10B Problems/Problem 2"
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==Solution== | ==Solution== | ||
− | We can synchronously multiply <math> {2^3} </math> to the polynomials both above and below the fraction bar. | + | We can synchronously multiply <math> {2^3} </math> to the polynomials both above and below the fraction bar. Thus, |
− | + | <cmath>\frac{2^3+2^3}{2^{-3}+2^{-3}}\\=\frac{2^6+2^6}{1+1}\\={2^6}. </cmath> | |
− | + | Hence, the fraction equals to <math>\boxed{{64 (\textbf{E})}}</math>. | |
+ | |||
+ | ==Video Solution== | ||
+ | https://youtu.be/vLFULrT_7yk | ||
+ | |||
+ | ~savannahsolver | ||
==See Also== | ==See Also== | ||
{{AMC10 box|year=2014|ab=B|num-b=1|num-a=3}} | {{AMC10 box|year=2014|ab=B|num-b=1|num-a=3}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Latest revision as of 10:28, 12 September 2020
Contents
Problem
What is ?
Solution
We can synchronously multiply to the polynomials both above and below the fraction bar. Thus, Hence, the fraction equals to .
Video Solution
~savannahsolver
See Also
2014 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 3 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.