Difference between revisions of "2014 AMC 10B Problems/Problem 4"
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==Solution== | ==Solution== | ||
| − | Let <math>m</math> be the cost of a muffin and <math>b</math> be the cost of a banana. From the given information, <cmath>2m+16b=2(4m+3b)=8m+6b\Rightarrow 10b=6m\Rightarrow m=\frac{10}{6}b=\text{(B)} \boxed{\frac{5}{3}b}</cmath>. | + | Let <math>m</math> be the cost of a muffin and <math>b</math> be the cost of a banana. From the given information, <cmath>2m+16b=2(4m+3b)=8m+6b\Rightarrow 10b=6m\Rightarrow m=\frac{10}{6}b=\text{(B) } \boxed{\frac{5}{3}b}</cmath>. |
| + | |||
| + | ==Video Solution== | ||
| + | https://youtu.be/7_-ZvunSC8w | ||
| + | |||
| + | ~savannahsolver | ||
==See Also== | ==See Also== | ||
{{AMC10 box|year=2014|ab=B|num-b=3|num-a=5}} | {{AMC10 box|year=2014|ab=B|num-b=3|num-a=5}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 13:11, 18 June 2020
Contents
Problem
Susie pays for 
muffins and 
bananas. Calvin spends twice as much paying for 
muffins and 
bananas. A muffin is how many times as expensive as a banana?
Solution
Let 
be the cost of a muffin and 
be the cost of a banana. From the given information, ![\[2m+16b=2(4m+3b)=8m+6b\Rightarrow 10b=6m\Rightarrow m=\frac{10}{6}b=\text{(B) } \boxed{\frac{5}{3}b}\]](http://latex.artofproblemsolving.com/2/9/d/29d6b94d062cae85119a105b3187dc866ed30ded.png)
.
Video Solution
~savannahsolver
See Also
| 2014 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by Problem 3 |
Followed by Problem 5 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
