Difference between revisions of "2014 AMC 10B Problems/Problem 8"
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==Solution== | ==Solution== | ||
− | Converting feet to yards and minutes to second, we see that the truck travels <math>\dfrac{b}{18}</math> yards every <math>t</math> seconds for <math>180</math> seconds. We see that he does <math>\dfrac{180}{t}</math> cycles of <math>\dfrac{b}{18}</math> yards. Multiplying, we get <math>\dfrac{180b}{18t}</math>, or <math> | + | Converting feet to yards and minutes to second, we see that the truck travels <math>\dfrac{b}{18}</math> yards every <math>t</math> seconds for <math>180</math> seconds. We see that he does <math>\dfrac{180}{t}</math> cycles of <math>\dfrac{b}{18}</math> yards. Multiplying, we get <math>\dfrac{180b}{18t}</math>, or <math>\dfrac{10b}{t}</math>, or <math>\boxed{(E)}</math> |
==See Also== | ==See Also== | ||
{{AMC10 box|year=2014|ab=B|num-b=7|num-a=9}} | {{AMC10 box|year=2014|ab=B|num-b=7|num-a=9}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 16:16, 20 February 2014
Problem
A truck travels feet every seconds. There are feet in a yard. How many yards does the truck travel in minutes?
Solution
Converting feet to yards and minutes to second, we see that the truck travels yards every seconds for seconds. We see that he does cycles of yards. Multiplying, we get , or , or
See Also
2014 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 7 |
Followed by Problem 9 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
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