Difference between revisions of "2014 AMC 8 Problems/Problem 1"

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==Problem==
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Harry and Terry are each told to calculate <math>8-(2+5)</math>. Harry gets the correct answer. Terry ignores the parentheses and calculates <math>8-2+5</math>. If Harry’s answer is <math>H</math> and Terry’s answer is <math>T</math>, what is <math>H-T</math>?
 
 
 
 
 
<math>\textbf{(A) }-10\qquad\textbf{(B) }-6\qquad\textbf{(C) }0\qquad\textbf{(D) }6\qquad \textbf{(E) }10</math>
 
  
 
==Solution==
 
==Solution==

Revision as of 09:18, 10 November 2019

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Solution

We have $H=8-7=1$ and $T=8-2+5=11$. Clearly $1-11=-10$ , so our answer is $\boxed{\textbf{(A)}-10}$.

See Also

2014 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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