Difference between revisions of "2014 AMC 8 Problems/Problem 10"
Sweetmango77 (talk | contribs) m (→Solution 2) |
Sweetmango77 (talk | contribs) m (→Solution 2) |
||
Line 10: | Line 10: | ||
− | ==Solution 2== | + | ==Solution 2 -SweetMango77== |
− | Since she was 12 when she took the seventh AMC 8, she should be <math>12-(7-1)=12-6=6</math> years old when the first AMC 8 occurred. Therefore, she was born or was 'age 0' in <math>1985-6=\boxed{\left(\text{A}\right)1979}</math>. | + | Since she was 12 when she took the seventh AMC 8, she should be <math>12-(7-1)=12-6=6</math> years old when the first AMC 8 occurred. Therefore, she was born or was 'age 0' in <math>1985-6=\boxed{\left(\text{A}\right)1979}</math>. |
==See Also== | ==See Also== | ||
{{AMC8 box|year=2014|num-b=9|num-a=11}} | {{AMC8 box|year=2014|num-b=9|num-a=11}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Latest revision as of 17:34, 28 October 2020
Problem
The first AMC was given in and it has been given annually since that time. Samantha turned years old the year that she took the seventh AMC . In what year was Samantha born?
Solution
The seventh AMC 8 would have been given in . If Samantha was 12 then, that means she was born 12 years ago, so she was born in .
Our answer is
Solution 2 -SweetMango77
Since she was 12 when she took the seventh AMC 8, she should be years old when the first AMC 8 occurred. Therefore, she was born or was 'age 0' in .
See Also
2014 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 9 |
Followed by Problem 11 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.