Difference between revisions of "2014 AMC 8 Problems/Problem 5"

(Solution)
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<math>\textbf{(A) }64\qquad\textbf{(B) }128\qquad\textbf{(C) }160\qquad\textbf{(D) }320\qquad \textbf{(E) }640</math>
 
<math>\textbf{(A) }64\qquad\textbf{(B) }128\qquad\textbf{(C) }160\qquad\textbf{(D) }320\qquad \textbf{(E) }640</math>
 
==Solution==
 
==Solution==
Margie can afford <math>20/4=5</math> gallons of gas. She can go <math>32*5=\boxed{160}</math> miles on this amount of gas.
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Margie can afford <math>20/4=5</math> gallons of gas. She can go <math>32\cdot5=\boxed{160}</math> miles on this amount of gas.
  
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2014|num-b=4|num-a=6}}
 
{{AMC8 box|year=2014|num-b=4|num-a=6}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 14:52, 28 November 2014

Problem

Margie's car can go $32$ miles on a gallon of gas, and gas currently costs $$4$ per gallon. How many miles can Margie drive on $$20$ worth of gas?

$\textbf{(A) }64\qquad\textbf{(B) }128\qquad\textbf{(C) }160\qquad\textbf{(D) }320\qquad \textbf{(E) }640$

Solution

Margie can afford $20/4=5$ gallons of gas. She can go $32\cdot5=\boxed{160}$ miles on this amount of gas.

See Also

2014 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 4
Followed by
Problem 6
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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