Difference between revisions of "2015 AMC 10A Problems/Problem 1"

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==Solution==
 
==Solution==
  
Simply evaluating gives <math>\boxed{\textbf{(C)}\frac15}</math>.
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Simply evaluating gives <math>\boxed{\textbf{(C) }\frac15}</math>.

Revision as of 12:35, 4 February 2015

Problem

What is the value of $(2^0-1+5^2-0)^{-1}\times5?$

$\textbf{(A)}\ -125\qquad\textbf{(B)}\ -120\qquad\textbf{(C)}\ \frac{1}{5}\qquad\textbf{(D)}}\ \frac{5}{24}\qquad\textbf{(E)}\ 25$ (Error compiling LaTeX. ! Extra }, or forgotten $.)


Solution

Simply evaluating gives $\boxed{\textbf{(C) }\frac15}$.

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