Difference between revisions of "2015 AMC 10A Problems/Problem 1"

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{{duplicate|[[2015 AMC 12A Problems|2015 AMC 12A #1]] and [[2015 AMC 10A Problems|2015 AMC 10B #1]]}}
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{{duplicate|[[2015 AMC 12A Problems|2015 AMC 12A #1]] and [[2015 AMC 10A Problems|2015 AMC 10A #1]]}}
 
==Problem==
 
==Problem==
  

Revision as of 20:41, 4 February 2015

The following problem is from both the 2015 AMC 12A #1 and 2015 AMC 10A #1, so both problems redirect to this page.

Problem

What is the value of $(2^0-1+5^2-0)^{-1}\times5?$

$\textbf{(A)}\ -125\qquad\textbf{(B)}\ -120\qquad\textbf{(C)}\ \frac{1}{5}\qquad\textbf{(D)}}\ \frac{5}{24}\qquad\textbf{(E)}\ 25$ (Error compiling LaTeX. ! Extra }, or forgotten $.)

Solution

$(2^0-1+5^2-0)^{-1}\times5$ $=(1-1+25-0)^{-1}\times5$ $=25^{-1}\times5$ $=\frac{1}{25}\times5$ $=\frac{1}{5}\implies{\boxed{\textbf{(C)}\ \frac{1}{5}}}$

See Also

2015 AMC 10A (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions
2015 AMC 12A (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png

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