Difference between revisions of "2015 AMC 10A Problems/Problem 23"

(Added problem)
(fixed ans choices)
Line 1: Line 1:
 
 
==Problem==
 
==Problem==
 
The zeroes of the function <math>f(x)=x^2-ax+2a</math> are integers .What is the sum of the possible values of a?
 
The zeroes of the function <math>f(x)=x^2-ax+2a</math> are integers .What is the sum of the possible values of a?
  
<math> \textbf{(A)}\ -125\qquad\textbf{(B)}\ -120\qquad\textbf{(C)}\ \frac{1}{5}\qquad\textbf{(D)}}\ \frac{5}{24}\qquad\textbf{(E)}\ 25</math>
+
<math> \textbf{(A)}\ 7\qquad\textbf{(B)}\ 8\qquad\textbf{(C)}\ 16\qquad\textbf{(D)}}\ 17\qquad\textbf{(E)}\ 18</math>
 +
 
  
 
==Solution==
 
==Solution==
 +
 +
SFFT.
  
 
==See Also==
 
==See Also==
{{AMC10 box|year=2015|ab=A|before=22|num-a=2}}
+
{{AMC10 box|year=2015|ab=A|before=First Problem|num-a=2}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 19:26, 4 February 2015

Problem

The zeroes of the function $f(x)=x^2-ax+2a$ are integers .What is the sum of the possible values of a?

$\textbf{(A)}\ 7\qquad\textbf{(B)}\ 8\qquad\textbf{(C)}\ 16\qquad\textbf{(D)}}\ 17\qquad\textbf{(E)}\ 18$ (Error compiling LaTeX. Unknown error_msg)


Solution

SFFT.

See Also

2015 AMC 10A (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png