Difference between revisions of "2015 AMC 10A Problems/Problem 7"

Revision as of 16:47, 4 February 2015

How many terms are in the arithmetic sequence 13, 16, 19,..., 70, 73?

$\textbf{(a)}\ 20 \qquad\textbf{(B)} \ 21 \qquad\textbf{(C)} \ 24 \qquad\textbf{(D)} \ 60 \qquad\textbf{(E)} \ 61$

73-13 is 60, so the amount of terms in the sequence 13, 16, 19,..., 70, 73 is the same as in the sequence 0, 3, 6,..., 57, 60.

In this sequence, the terms are the multiples of 3 going up to 60, and there are 20 multiples of 3 in 60.

However, one more must be added to include the first term. So, the answer is $\boxed{\textbf{(B) }21}$ .

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 <math> \textbf{(a)}\ 20 \qquad\textbf{(B)} \ 21 \qquad\textbf{(C)} \ 24 \qquad\textbf{(D)} \ 60 \qquad\textbf{(E)} \ 61 </math>
+==Solution==
+-13 is 60, so the amount of terms in the sequence 13, 16, 19,..., 70, 73 is the same as in the sequence 0, 3, 6,..., 57, 60.
+In this sequence, the terms are the multiples of 3 going up to 60, and there are 20 multiples of 3 in 60.
+However, one more must be added to include the first term. So, the answer is <math>\boxed{\textbf{(B) }21}</math>.