Difference between revisions of "2015 AMC 10B Problems/Problem 2"
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==Problem== | ==Problem== | ||
| − | Marie does three equally time-consuming tasks in a row without taking breaks. She begins the first task at 1:00 PM and finishes the second task at 2:40 PM. When does she finish the third task? | + | Marie does three equally time-consuming tasks in a row without taking breaks. She begins the first task at <math>1\!:\!00</math> PM and finishes the second task at <math>2\!:\!40</math> PM. When does she finish the third task? |
<math> \textbf{(A) }\text{3:10 PM}\qquad\textbf{(B) }\text{3:30 PM}\qquad\textbf{(C) }\text{4:00 PM}\qquad\textbf{(D) }\text{4:10 PM}\qquad\textbf{(E) }\text{4:30 PM} </math> | <math> \textbf{(A) }\text{3:10 PM}\qquad\textbf{(B) }\text{3:30 PM}\qquad\textbf{(C) }\text{4:00 PM}\qquad\textbf{(D) }\text{4:10 PM}\qquad\textbf{(E) }\text{4:30 PM} </math> | ||
Revision as of 17:04, 13 July 2020
Contents
Problem
Marie does three equally time-consuming tasks in a row without taking breaks. She begins the first task at 
PM and finishes the second task at 
PM. When does she finish the third task?
Solution
Marie finishes 2 tasks in 
hour and 
minutes. Therefore, one task should take 
minutes to finish. minutes after PM is 
PM, so our answer is 
Video Solution
~savannahsolver
See Also
| 2015 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 3 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
