Difference between revisions of "2015 AMC 10B Problems/Problem 5"
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==Solution== | ==Solution== | ||
Because Marta was <math>6</math>th, Jack was <math>5</math>th, so Todd was <math>3</math>rd. Thus, Rand was <math>2</math>nd and the 8th place finisher was <math>\boxed{\mathbf{(B)}\ \mathrm{Hikmet}}</math> | Because Marta was <math>6</math>th, Jack was <math>5</math>th, so Todd was <math>3</math>rd. Thus, Rand was <math>2</math>nd and the 8th place finisher was <math>\boxed{\mathbf{(B)}\ \mathrm{Hikmet}}</math> | ||
+ | |||
+ | ==Video Solution== | ||
+ | https://youtu.be/61oSoeT0ULA | ||
+ | |||
+ | ~savannahsolver | ||
==See Also== | ==See Also== | ||
{{AMC10 box|year=2015|ab=B|num-b=4|num-a=6}} | {{AMC10 box|year=2015|ab=B|num-b=4|num-a=6}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Latest revision as of 14:07, 25 June 2020
Contents
Problem
David, Hikmet, Jack, Marta, Rand, and Todd were in a -person race with other people. Rand finished places ahead of Hikmet. Marta finished place behind Jack. David finished places behind Hikmet. Jack finished places behind Todd. Todd finished place behind Rand. Marta finished in th place. Who finished in th place?
Solution
Because Marta was th, Jack was th, so Todd was rd. Thus, Rand was nd and the 8th place finisher was
Video Solution
~savannahsolver
See Also
2015 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 4 |
Followed by Problem 6 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
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