Difference between revisions of "2015 AMC 12B Problems/Problem 2"

(See Also)
(See Also)
Line 7: Line 7:
  
 
==See Also==
 
==See Also==
{{AMC12 box|year=2015|ab=B|num-a=1|num-b=3}}
+
{{AMC12 box|year=2015|ab=B|num-a=3|num-b=1}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 11:43, 2 March 2015

Problem

Solution

See Also

2015 AMC 12B (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png