Difference between revisions of "2015 AMC 8 Problems/Problem 1"

Revision as of 15:52, 16 January 2021

Problem

How many square yards of carpet are required to cover a rectangular floor that is $12$ feet long and $9$ feet wide? (There are 3 feet in a yard.)

$\textbf{(A) }12\qquad\textbf{(B) }36\qquad\textbf{(C) }108\qquad\textbf{(D) }324\qquad \textbf{(E) }972$

Solutions

Solution 1

First, we multiply $12\cdot9$ . To get that you need $108$ square feet of carpet you need to cover. Since there are $9$ square feet in a square yard, you divide $108$ by $9$ to get $12$ square yards, so our answer is $\bold{\boxed{\textbf{(A)}~12}}$ .

Solution 2

Since there are $3$ feet in a yard, we divide $9$ by $3$ to get $3$ , and $12$ by $3$ to get $4$ . To find the area of the carpet, we then multiply these two values together to get $\boxed{\textbf{(A)}~12}$ .

2015 AMC 8 (Problems • Answer Key • Resources)
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All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

Placement:Easy Geometry

@@ Line 9: / Line 9: @@
 First, we multiply <math>12\cdot9</math>. To get that you need <math>108</math> square feet of carpet you need to cover.  Since there are <math>9</math> square feet in a square yard, you divide <math>108</math> by <math>9</math> to get <math>12</math> square yards, so our answer is <math>\bold{\boxed{\textbf{(A)}~12}}</math>.
-==Solution 2==
+===Solution 2===
 Since there are <math>3</math> feet in a yard, we divide <math>9</math> by <math>3</math> to get <math>3</math>, and <math>12</math> by <math>3</math> to get <math>4</math>. To find the area of the carpet, we then multiply these two values together to get <math>\boxed{\textbf{(A)}~12}</math>.

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