# Difference between revisions of "2016 AMC 10B Problems/Problem 19"

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\textbf{(D)}~\frac{10}{91}\qquad | \textbf{(D)}~\frac{10}{91}\qquad | ||

\textbf{(E)}~\frac19</math> | \textbf{(E)}~\frac19</math> | ||

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+ | ==Solution== | ||

+ | <math>\textbf{(D)}~\frac{10}{91}</math> | ||

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+ | solution by ngeorge |

## Revision as of 09:29, 21 February 2016

## Problem

Rectangle has and . Point lies on so that , point lies on so that . and point lies on so that . Segments and intersect at and , respectively. What is the value of ?

## Solution

solution by ngeorge