2016 AMC 10B Problems/Problem 8

Revision as of 10:49, 21 February 2016 by Xturtlex (talk | contribs) (Solution)

Problem

What is the tens digit of $2015^{2016}-2017?$

$\textbf{(A)}\ 0 \qquad \textbf{(B)}\ 1 \qquad \textbf{(C)}\ 3 \qquad \textbf{(D)}\ 5 \qquad \textbf{(E)}\ 8$

Solution

We notice that $2015^{n}$ is 25 (mod 100) when n is even and 75 (mod 100) when n is odd. (check for yourself). Since 2016 is even, $2015^{2016}$ is 25 (mod 100) and $2015^{2016}-2017 \equiv 25 - 17 \equiv 08 (mod 100)$ So the answer is $\textbf{(A)}\ 0 \qquad$ solution by Wwang