Difference between revisions of "2016 AMC 12B Problems/Problem 12"
(→Solution) |
|||
| Line 6: | Line 6: | ||
==Solution== | ==Solution== | ||
| + | {{solution}} | ||
==See Also== | ==See Also== | ||
{{AMC12 box|year=2016|ab=B|num-b=11|num-a=13}} | {{AMC12 box|year=2016|ab=B|num-b=11|num-a=13}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 18:27, 21 February 2016
Problem
All the numbers 
are written in a 
array of squares, one number in each square, in such a way that if two numbers of consecutive then they occupy squares that share an edge. The numbers in the four corners add up to 
. What is the number in the center?
Solution
This problem needs a solution. If you have a solution for it, please help us out by adding it.
See Also
| 2016 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 11 |
Followed by Problem 13 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
