Difference between revisions of "2016 AMC 8 Problems/Problem 1"

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== Problem ==
 
The longest professional tennis match ever played lasted a total of <math>11</math> hours and <math>5</math> minutes. How many minutes was this?
 
The longest professional tennis match ever played lasted a total of <math>11</math> hours and <math>5</math> minutes. How many minutes was this?
  
 
<math>\textbf{(A) }605\qquad\textbf{(B) }655\qquad\textbf{(C) }665\qquad\textbf{(D) }1005\qquad \textbf{(E) }1105</math>
 
<math>\textbf{(A) }605\qquad\textbf{(B) }655\qquad\textbf{(C) }665\qquad\textbf{(D) }1005\qquad \textbf{(E) }1105</math>
  
==Solution==
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== Solutions ==
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===Solution 1===
 
It is best to split 11 hours and 5 minutes into 2 parts, one of 11 hours and another of 5 minutes.  We know that there is <math>60</math> minutes in a hour.  Therefore, there are <math>11 \cdot 60 = 660</math> minutes in 11 hours.  Adding the second part(the 5 minutes) we get <math>660 + 5 = \boxed{\textbf{(C)}\ 665}</math>.
 
It is best to split 11 hours and 5 minutes into 2 parts, one of 11 hours and another of 5 minutes.  We know that there is <math>60</math> minutes in a hour.  Therefore, there are <math>11 \cdot 60 = 660</math> minutes in 11 hours.  Adding the second part(the 5 minutes) we get <math>660 + 5 = \boxed{\textbf{(C)}\ 665}</math>.
  
==Solution 2==
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===Solution 2===
 
The best method comes when you remember your multiplication tables. Thus trivial, we get our answer of <math>\boxed{{(C) }   
 
The best method comes when you remember your multiplication tables. Thus trivial, we get our answer of <math>\boxed{{(C) }   
  665}</math>.  
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  665}</math>.
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===Solution 3===
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11 hours 5 min = <math>(11 \cdot 60) + 5 \text{min}  = 665 \text{min}</math>, therefore
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<math>\boxed{{(C) } 
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}</math>.
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Carmen
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==Video Solution (THINKING CREATIVELY!!!)==
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https://youtu.be/-T0AZIsu4DE
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~Education, the Study of Everything
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==Video Solution==
 
==Video Solution==
 
https://www.youtube.com/watch?v=LqnQQcUVJmA (has questions 1-5)
 
https://www.youtube.com/watch?v=LqnQQcUVJmA (has questions 1-5)
  
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https://youtu.be/1cu8fT2UJCw
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 +
~savannahsolver
  
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==See Also==
 
{{AMC8 box|year=2016|before=First Problem|num-a=2}}
 
{{AMC8 box|year=2016|before=First Problem|num-a=2}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Latest revision as of 23:03, 2 April 2023

Problem

The longest professional tennis match ever played lasted a total of $11$ hours and $5$ minutes. How many minutes was this?

$\textbf{(A) }605\qquad\textbf{(B) }655\qquad\textbf{(C) }665\qquad\textbf{(D) }1005\qquad \textbf{(E) }1105$

Solutions

Solution 1

It is best to split 11 hours and 5 minutes into 2 parts, one of 11 hours and another of 5 minutes. We know that there is $60$ minutes in a hour. Therefore, there are $11 \cdot 60 = 660$ minutes in 11 hours. Adding the second part(the 5 minutes) we get $660 + 5 = \boxed{\textbf{(C)}\ 665}$.

Solution 2

The best method comes when you remember your multiplication tables. Thus trivial, we get our answer of $\boxed{{(C) }    665}$.

Solution 3

11 hours 5 min = $(11 \cdot 60) + 5 \text{min}  = 665 \text{min}$, therefore $\boxed{{(C) }   }$.

Carmen

Video Solution (THINKING CREATIVELY!!!)

https://youtu.be/-T0AZIsu4DE

~Education, the Study of Everything


Video Solution

https://www.youtube.com/watch?v=LqnQQcUVJmA (has questions 1-5)

https://youtu.be/1cu8fT2UJCw

~savannahsolver

See Also

2016 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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