2016 AMC 8 Problems/Problem 18

Revision as of 12:33, 23 November 2016 by Wirecat (talk | contribs) (Solution)

18. In an All-Area track meet, $216$ sprinters enter a $100-$meter dash competition. The track has $6$ lanes, so only $6$ sprinters can compete at a time. At the end of each race, the five non-winners are eliminated, and the winner will compete again in a later race. How many races are needed to determine the champion sprinter?


$(A)\mbox{ }36\mbox{           }(B)\mbox{ }42\mbox{           }(C)\mbox{ }43\mbox{           }(D)\mbox{ }60\mbox{           }(E)\mbox{ }72\mbox{           }$

Solution

From any nth race, only $\frac{1}{6}$ will continue on. Since we wish to find the total number of races, a column representing the races over time is ideal. Starting with the first race: \[\frac{216}{6}=36\] \[\frac{36}{6}=6\] \[\frac{6}{6}=1\] Adding all of the numbers in the second column yields $43 \rightarrow \boxed{C}$

2016 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 17
Followed by
Problem 19
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png

\end{align}