Difference between revisions of "2016 AMC 8 Problems/Problem 3"

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==Solution==
 
==Solution==
 
We see that <math>80-70=10</math> and <math>90-70=20</math>.  We then find that <math>10+20=30</math>.  We want our average to be <math>70</math>, so we find <math>70-30=40</math>.  So our final answer is <math>\boxed{\textbf{(A) }40}</math>.
 
We see that <math>80-70=10</math> and <math>90-70=20</math>.  We then find that <math>10+20=30</math>.  We want our average to be <math>70</math>, so we find <math>70-30=40</math>.  So our final answer is <math>\boxed{\textbf{(A) }40}</math>.
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{{AMC8 box|year=2016|num-b=2|num-a=4}}
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{{MAA Notice}}

Revision as of 09:44, 23 November 2016

3. Four students take an exam. Three of their scores are $70, 80,$ and $90$. If the average of their four scores is $70$, then what is the remaining score?

$\textbf{(A) }40\qquad\textbf{(B) }50\qquad\textbf{(C) }55\qquad\textbf{(D) }60\qquad \textbf{(E) }70$

Solution

We see that $80-70=10$ and $90-70=20$. We then find that $10+20=30$. We want our average to be $70$, so we find $70-30=40$. So our final answer is $\boxed{\textbf{(A) }40}$.

2016 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 2
Followed by
Problem 4
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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