Difference between revisions of "2016 AMC 8 Problems/Problem 6"

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==Solution==
 
==Solution==
We first notice that the median name will be the <math>10^{\mbox{th}}</math> name. We take all the <math>3</math> letter names away from the list to see that the <math>3^{\mbox{rd}}</math> name in the new table is the desired length. Since there are <math>3</math> names that are <math>4</math> letters long, the median name length is <math>\textbf{(B)} 4</math>.  
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We first notice that the median name will be the <math>10^{\mbox{th}}</math> name. We take all the <math>3</math> letter names away from the list to see that the <math>3^{\mbox{rd}}</math> name in the new table is the desired length. Since there are <math>3</math> names that are <math>4</math> letters long, the median name length is <math>\text{(B)}</math> <math>4</math>.  
  
 
{{AMC8 box|year=2016|num-b=5|num-a=7}}
 
{{AMC8 box|year=2016|num-b=5|num-a=7}}

Revision as of 13:53, 23 November 2016

The following bar graph represents the length (in letters) of the names of 19 people. What is the median length of these names? $\textbf{(A) }3\qquad\textbf{(B) }4\qquad\textbf{(C) }5\qquad\textbf{(D) }6\qquad \textbf{(E) }7$

Solution

We first notice that the median name will be the $10^{\mbox{th}}$ name. We take all the $3$ letter names away from the list to see that the $3^{\mbox{rd}}$ name in the new table is the desired length. Since there are $3$ names that are $4$ letters long, the median name length is $\text{(B)}$ $4$.

2016 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 5
Followed by
Problem 7
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All AJHSME/AMC 8 Problems and Solutions