Difference between revisions of "2016 AMC 8 Problems/Problem 7"
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− | We know that our answer must have an odd exponent in order for it to not be a square. | + | We know that our answer must have an odd exponent in order for it to not be a square. Because <math>4</math> is a perfect square, <math>4^{2019}</math> is not prime, so our answer must be <math>\boxed{\textbf{(B) }2^{2017}}</math>. |
{{AMC8 box|year=2016|num-b=6|num-a=8}} | {{AMC8 box|year=2016|num-b=6|num-a=8}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 20:07, 27 November 2016
Which of the following numbers is not a perfect square?
Solution
We know that our answer must have an odd exponent in order for it to not be a square. Because is a perfect square, is not prime, so our answer must be .
2016 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 6 |
Followed by Problem 8 | |
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All AJHSME/AMC 8 Problems and Solutions |
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