# Difference between revisions of "2016 IMO Problems/Problem 5"

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The equation | The equation | ||

− | <center>(x-1)(x-2)\cdots(x-2016)=(x-1)(x-2)\cdots (x-2016)<math></center> | + | <center><math>(x-1)(x-2)\cdots(x-2016)=(x-1)(x-2)\cdots (x-2016)</math></center> |

− | is written on the board, with < | + | is written on the board, with <math>2016</math> linear factors on each side. What is the least possible value of <math>k</math> for which it is possible to erase exactly <math>k</math> of these <math>4032</math> linear factors so that at least one factor remains on each side and the resulting equation has no real solutions? |

## Latest revision as of 20:16, 26 December 2019

The equation

is written on the board, with linear factors on each side. What is the least possible value of for which it is possible to erase exactly of these linear factors so that at least one factor remains on each side and the resulting equation has no real solutions?