Difference between revisions of "2017 AMC 10A Problems/Problem 11"
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Solving, we find that <math>x = \boxed{\textbf{(D)}\ 20}</math>. | Solving, we find that <math>x = \boxed{\textbf{(D)}\ 20}</math>. | ||
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==Diagram== | ==Diagram== |
Revision as of 08:32, 9 February 2017
Contents
Problem
The region consisting of all point in three-dimensional space within 3 units of line segment has volume 216. What is the length ?
Solution 1
In order to solve this problem, we must first visualize what the region contained looks like. We know that, in a three dimensional plane, the region consisting of all points within units of a point would be a sphere with radius . However, we need to find the region containing all points within 3 units of a segment. It can be seen that our region is a cylinder with two hemispheres on either end. We know the volume of our region, so we set up the following equation (the volume of our cylinder + the volume of our two hemispheres will equal ):
, where is equal to the length of our line segment.
Solving, we find that .
Diagram
http://i.imgur.com/cwNt293.png
See Also
2017 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 10 |
Followed by Problem 12 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.