Difference between revisions of "2017 AMC 10A Problems/Problem 19"
m |
|||
| Line 1: | Line 1: | ||
| − | + | ==Problem== | |
| + | Alice refuses to sit next to either Bob or Carla. Derek refuses to sit next to Eric. How many ways are there for the five of them to sit in a row of 5 chairs under these conditions? | ||
<math>(A) 12</math> <math>(B) 16</math> <math>(C) 28</math> <math>(D) 32</math> (<math>E) 40</math> | <math>(A) 12</math> <math>(B) 16</math> <math>(C) 28</math> <math>(D) 32</math> (<math>E) 40</math> | ||
| + | |||
| + | ==See Also== | ||
| + | {{AMC10 box|year=2017|ab=A|num-b=18|num-a=20}} | ||
| + | {{MAA Notice}} | ||
Revision as of 17:45, 8 February 2017
Problem
Alice refuses to sit next to either Bob or Carla. Derek refuses to sit next to Eric. How many ways are there for the five of them to sit in a row of 5 chairs under these conditions?
(
See Also
| 2017 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by Problem 18 |
Followed by Problem 20 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
