2017 AMC 10A Problems/Problem 2

Revision as of 22:00, 8 February 2017 by Hiabc (talk | contribs) (Solution)

Problem

Pablo buys popsicles for his friends. The store sells single popsicles for $1 each, 3-popsicle boxes for $2 each, and 5-popsicle boxes for $3. What is the greatest number of popsicles that Pablo can buy with $8?

$\textbf{(A)}\ 8\qquad\textbf{(B)}\ 11\qquad\textbf{(C)}\ 12\qquad\textbf{(D)}\ 13\qquad\textbf{(E)}\ 15$

Solution

$3 boxes give us the most popsicles/dollar, so we want to buy as many of those as possible. After buying 2, we have $2 left. We cannot buy a third $3 box, so we opt for the $2 box instead (since it has a higher popsicles/dollar ratio than the $1 pack). We're now out of money. We bought $5+5+3=13$ popsicles, so the answer is $\boxed{\textbf{(D) }13}$.

See Also

2017 AMC 10A (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
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All AMC 10 Problems and Solutions

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