Difference between revisions of "2017 AMC 10B Problems/Problem 11"

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<math>60\% \cdot 20\% = 12\%</math> of the people that claim that they like dancing say they dislike it, and <math>40\% \cdot 90\% = 36\%</math> of the people that claim that they dislike dancing actually dislike it. Therefore, the answer is <math>\frac{12\%}{12\%+36\%} = \boxed{\textbf{(D) } 25\%}</math>.
 
<math>60\% \cdot 20\% = 12\%</math> of the people that claim that they like dancing say they dislike it, and <math>40\% \cdot 90\% = 36\%</math> of the people that claim that they dislike dancing actually dislike it. Therefore, the answer is <math>\frac{12\%}{12\%+36\%} = \boxed{\textbf{(D) } 25\%}</math>.
  
==Video Solution & Solution ==
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==Video Solution==
 
https://youtu.be/93lThricxLE
 
https://youtu.be/93lThricxLE
  

Revision as of 18:46, 17 January 2021

Problem

At Typico High School, $60\%$ of the students like dancing, and the rest dislike it. Of those who like dancing, $80\%$ say that they like it, and the rest say that they dislike it. Of those who dislike dancing, $90\%$ say that they dislike it, and the rest say that they like it. What fraction of students who say they dislike dancing actually like it?

$\textbf{(A)}\ 10\%\qquad\textbf{(B)}\ 12\%\qquad\textbf{(C)}\ 20\%\qquad\textbf{(D)}\ 25\%\qquad\textbf{(E)}\ 33\frac{1}{3}\%$

Solution 1

$60\% \cdot 20\% = 12\%$ of the people that claim that they like dancing say they dislike it, and $40\% \cdot 90\% = 36\%$ of the people that claim that they dislike dancing actually dislike it. Therefore, the answer is $\frac{12\%}{12\%+36\%} = \boxed{\textbf{(D) } 25\%}$.

Video Solution

https://youtu.be/93lThricxLE

~savannahsolver

See Also

2017 AMC 10B (ProblemsAnswer KeyResources)
Preceded by
Problem 10
Followed by
Problem 12
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

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