Difference between revisions of "2017 AMC 10B Problems/Problem 24"
(→Problem 24) |
m (→Problem 24) |
||
| Line 4: | Line 4: | ||
<math>\textbf{(A)}\ 48\qquad\textbf{(B)}\ 60\qquad\textbf{(C)}\ 108\qquad\textbf{(D)}\ 120\qquad\textbf{(E)}\ 169</math> | <math>\textbf{(A)}\ 48\qquad\textbf{(B)}\ 60\qquad\textbf{(C)}\ 108\qquad\textbf{(D)}\ 120\qquad\textbf{(E)}\ 169</math> | ||
| − | + | ==Solution== | |
==See Also== | ==See Also== | ||
{{AMC10 box|year=2017|ab=A|num-b=23|num-a=25}} | {{AMC10 box|year=2017|ab=A|num-b=23|num-a=25}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 10:27, 16 February 2017
Problem 24
The vertices of an equilateral triangle lie on the hyperbola 
, and a vertex of this hyperbola is the centroid of the triangle. What is the square of the area of the triangle?
Solution
See Also
| 2017 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by Problem 23 |
Followed by Problem 25 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
