Difference between revisions of "2017 AMC 10B Problems/Problem 4"
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Substituting each <math>x</math> and <math>y</math> with <math>1</math>, we see that the given equation holds true, as <math>\frac{3(1)+1}{1-3(1)} = -2</math>. Thus, <math>\frac{x+3y}{3x-y}=\boxed{\textbf{(D)}\ 2}</math> | Substituting each <math>x</math> and <math>y</math> with <math>1</math>, we see that the given equation holds true, as <math>\frac{3(1)+1}{1-3(1)} = -2</math>. Thus, <math>\frac{x+3y}{3x-y}=\boxed{\textbf{(D)}\ 2}</math> | ||
Revision as of 17:14, 14 March 2017
Problem
Supposed that and are nonzero real numbers such that . What is the value of ?
Solution
Rearranging, we find , or Substituting, we can convert the second equation into
Solution yoyoyo
Substituting each and with , we see that the given equation holds true, as . Thus,
2017 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 3 |
Followed by Problem 5 | |
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All AMC 10 Problems and Solutions |
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