Difference between revisions of "2017 AMC 10B Problems/Problem 8"
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===Solution 2=== | ===Solution 2=== | ||
Calculating the equation of the line running between points <math>B</math> and <math>D</math>, <math>y = -2x + 1</math>. The only coordinate of <math>C</math> that is also on this line is <math>\boxed{\textbf{(C) } (-4,9)}</math>. | Calculating the equation of the line running between points <math>B</math> and <math>D</math>, <math>y = -2x + 1</math>. The only coordinate of <math>C</math> that is also on this line is <math>\boxed{\textbf{(C) } (-4,9)}</math>. | ||
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+ | ===Solution 3=== | ||
+ | Similar to the first solution, because the triangle is isosceles, then the line drawn in the middle separates the triangle into two smaller congruent triangles. To get from <math>B</math> to the <math>D</math>r, we go to the right <math>3</math> and up <math>6</math>. Then to get to point <math>C</math> from point <math>D</math>, we go to the right <math>3</math> and up <math>6</math>, getting us the coordinates <math>\boxed{\textbf{(C) } (-4,9)}</math>. ~<math>\text{KLBBC}</math> | ||
+ | |||
+ | ==Video Solution== | ||
+ | https://youtu.be/4rRckA3gcPU | ||
+ | |||
+ | ~savannahsolver | ||
+ | |||
+ | ==Video Solution 2== | ||
+ | https://youtu.be/XRfOULUmWbY?t=367 | ||
+ | |||
+ | ~IceMatrix | ||
==See Also== | ==See Also== | ||
{{AMC10 box|year=2017|ab=B|num-b=7|num-a=9}} | {{AMC10 box|year=2017|ab=B|num-b=7|num-a=9}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Latest revision as of 03:11, 4 December 2020
Contents
Problem
Points and are vertices of with . The altitude from meets the opposite side at . What are the coordinates of point ?
Solutions
Solution 1
Since , then is isosceles, so . Therefore, the coordinates of are .
Solution 2
Calculating the equation of the line running between points and , . The only coordinate of that is also on this line is .
Solution 3
Similar to the first solution, because the triangle is isosceles, then the line drawn in the middle separates the triangle into two smaller congruent triangles. To get from to the r, we go to the right and up . Then to get to point from point , we go to the right and up , getting us the coordinates . ~
Video Solution
~savannahsolver
Video Solution 2
https://youtu.be/XRfOULUmWbY?t=367
~IceMatrix
See Also
2017 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 7 |
Followed by Problem 9 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.