# Difference between revisions of "2017 AMC 8 Problems/Problem 11"

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Since the number of tiles lying on both diagonals is <math>37</math>, counting one tile twice, there are <math>37=2x-1\implies x=19</math> tiles on each side. Hence, our answer is <math>19^2=361=\boxed{\textbf{(C)}\ 361}</math>. | Since the number of tiles lying on both diagonals is <math>37</math>, counting one tile twice, there are <math>37=2x-1\implies x=19</math> tiles on each side. Hence, our answer is <math>19^2=361=\boxed{\textbf{(C)}\ 361}</math>. | ||

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## Revision as of 06:13, 7 November 2020

## Problem 11

A square-shaped floor is covered with congruent square tiles. If the total number of tiles that lie on the two diagonals is 37, how many tiles cover the floor?

## Solution

Since the number of tiles lying on both diagonals is , counting one tile twice, there are tiles on each side. Hence, our answer is .

ok boomeer