Difference between revisions of "2017 AMC 8 Problems/Problem 2"
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==Solution 2== | ==Solution 2== | ||
− | We're being asked for the total number of votes cast -- that represents <math>100\%</math> of the total number of votes | + | We're being asked for the total number of votes cast -- that represents <math>100\%</math> of the total number of votes. Brenda received <math>36</math> votes, which is <math>\frac{30}{100} = \frac{3}{10}</math> of the total number of votes. Multiplying <math>36</math> by <math>\frac{10}{3},</math> we get the total number of votes, which is <math>\boxed{\textbf{(E)}\ 120}.</math> |
==See Also== | ==See Also== |
Revision as of 11:20, 26 October 2019
Contents
Problem 2
Alicia, Brenda, and Colby were the candidates in a recent election for student president. The pie chart below shows how the votes were distributed among the three candidates. If Brenda received 36 votes, then how many votes were cast all together?
Solution 1
Let be the total amount of votes casted. From the chart, Brenda received of the votes and had votes. We can express this relationship as . Solving for , we get
Solution 2
We're being asked for the total number of votes cast -- that represents of the total number of votes. Brenda received votes, which is of the total number of votes. Multiplying by we get the total number of votes, which is
See Also
2017 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 3 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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