Difference between revisions of "2017 AMC 8 Problems/Problem 4"
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<math>\textbf{(A) }210\qquad\textbf{(B) }240\qquad\textbf{(C) }2100\qquad\textbf{(D) }2400\qquad\textbf{(E) }24000</math> | <math>\textbf{(A) }210\qquad\textbf{(B) }240\qquad\textbf{(C) }2100\qquad\textbf{(D) }2400\qquad\textbf{(E) }24000</math> | ||
| − | ==Solution | + | ==Solution== |
| − | We can approximate <math>7,928,564</math> to <math>8,000,000,</math> and <math>0.000315</math> to <math>0.0003.</math> Multiplying the two yields <math>2400.</math> This gives our answer to be <math>\ | + | We can approximate <math>7,928,564</math> to <math>8,000,000,</math> and <math>0.000315</math> to <math>0.0003.</math> Multiplying the two yields <math>2400.</math> This gives our answer to be <math>\boxed{\textbf{(D)}\ 2400}.</math> |
Revision as of 15:23, 22 November 2017
Problem 4
When 
is multiplied by 
the product is closest to which of the following?
Solution
We can approximate to 
and to 
Multiplying the two yields 
This gives our answer to be 
